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D( x )
x < 0
x < 0
x in <0:+oo)
x^(5/4)-(4*x^(5/8))+4 = 0
x^(5/4)-4*x^(5/8)+4 = 0
t_1 = x^(5/8)
1*t_1^2-4*t_1^1+4 = 0
t_1^2-4*t_1+4 = 0
DELTA = (-4)^2-(1*4*4)
DELTA = 0
t_1 = 4/(1*2)
t_1 = 2 or t_1 = 2
t_1 = 2
x^(5/8)-2 = 0
1*x^(5/8) = 2 // : 1
x^(5/8) = 2
x^(5/8) = 2 // ^ 8
x^5 = 256 // ^ 1/5
x = 2*8^(1/5)
t_1 = 2
x^(5/8)-2 = 0
1*x^(5/8) = 2 // : 1
x^(5/8) = 2
x^(5/8) = 2 // ^ 8
x^5 = 256 // ^ 1/5
x = 2*8^(1/5)
x in { 2*8^(1/5), 2*8^(1/5) }
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